5c^2+4c=1

Solution for 5c^2+4c=1 equation:

Simplifying
5c2 + 4c = 1

Reorder the terms:
4c + 5c2 = 1

Solving
4c + 5c2 = 1

Solving for variable 'c'.

Reorder the terms:
-1 + 4c + 5c2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 4c + 5c2 = 0

Factor a trinomial.
(-1 + -1c)(1 + -5c) = 0

Subproblem 1
Set the factor '(-1 + -1c)' equal to zero and attempt to solve:

Simplifying
-1 + -1c = 0

Solving
-1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1c = 0 + 1
-1c = 0 + 1

Combine like terms: 0 + 1 = 1
-1c = 1

Divide each side by '-1'.
c = -1

Simplifying
c = -1
Subproblem 2
Set the factor '(1 + -5c)' equal to zero and attempt to solve:

Simplifying
1 + -5c = 0

Solving
1 + -5c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -5c = 0 + -1
-5c = 0 + -1

Combine like terms: 0 + -1 = -1
-5c = -1

Divide each side by '-5'.
c = 0.2

Simplifying
c = 0.2
Solution
c = {-1, 0.2}